ECE492 Section 2 Notes - Revision history

Eddynetweb: Added additional day content.

2022-03-07T20:59:11Z

Added additional day content.

@@ Line 34: / Line 34: @@
 * Saturation: Both junction are forward biased.
 * Active: One junction is forward biased, another one is reverse biased.
 === Header 2 ===

Eddynetweb: Section 2.1 additional notes

2022-03-02T19:42:22Z

Section 2.1 additional notes

← Older revision		Revision as of 19:42, 2 March 2022
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	There are two types of BJTs:		There are two types of BJTs:
	* NPN, in which		* NPN, in which...
	* PNP		* PNP, in which...

	Now we'll cover (B) Common Emitter Current gain:		Now we'll cover (B) Common Emitter Current gain:
Line 26:		Line 26:
	...and (Alpha) Common Base Current Gain:		...and (Alpha) Common Base Current Gain:
	* <math>Alpha = \frac{B}{B+1} = \frac{I_{c}}{I_{e}}</math>		* <math>Alpha = \frac{B}{B+1} = \frac{I_{c}}{I_{e}}</math>

			V-I Characteristics of Transistors:
			* AAAA

			NPN Transistor Example:
			* Cut Off: Both junction are reverse biased.
			* Saturation: Both junction are forward biased.
			* Active: One junction is forward biased, another one is reverse biased.

	=== Header 2 ===		=== Header 2 ===

Eddynetweb: Section 2.1 created for ECE492!

2022-03-02T19:15:40Z

Section 2.1 created for ECE492!

New page

Welcome! Notes for Spring 2022 Electronic Circuits course. Will make this more pretty as things evolve.

My goal is to make Electronic Circuits so easily digestible, you could teach a middle schooler. We'll see if this works.

== Prologue ==

Hey how are you. I will insert something here later. :)

== Section 2.1 ==

We'll begin by covering a '''Bi-polar Junction Transistor''', also known as BJT.

What is it exactly? Well, it's a transistor.
* It is a 3 terminal devices.
* It is a unsymmetrical device.
* It amplifies the signal.

There are two types of BJTs:
* NPN, in which
* PNP

Now we'll cover (B) Common Emitter Current gain:
* <math>B=\frac{I_{c}}{I_{b}}</math>
* 50 < B < 200

...and (Alpha) Common Base Current Gain:
* <math>Alpha = \frac{B}{B+1} = \frac{I_{c}}{I_{e}}</math>

=== Header 2 ===

It sometimes allow current, and sometimes it doesn't.

===Assignment 1.1===

We'll take this <math>x_{3}=\frac{9}{3}</math> and plug it into <math>2x_{2}+x_{3}=5</math> to find x<sub>2</sub>:

<math>
\begin{align}
2x_{2}+x_{3}=5 \\
x_{3}=\frac{9}{3} \\
\text{Plug in } x_{3}=\frac{9}{3} \text{ into } 2x_{2}+x_{3}=5 \text{:} \\
2x_{2}+\frac{9}{3}=5 \\
2x_{2}=2 \\
x_{2}=1
\end{align}
</math>