ECE492 Section 2 Notes: Difference between revisions
Jump to navigation
Jump to search
Eddynetweb (talk | contribs) (Section 2.1 created for ECE492!) |
Eddynetweb (talk | contribs) (Section 2.1 additional notes) |
||
Line 17: | Line 17: | ||
There are two types of BJTs: | There are two types of BJTs: | ||
* NPN, in which | * NPN, in which... | ||
* PNP | * PNP, in which... | ||
Now we'll cover (B) Common Emitter Current gain: | Now we'll cover (B) Common Emitter Current gain: | ||
Line 26: | Line 26: | ||
...and (Alpha) Common Base Current Gain: | ...and (Alpha) Common Base Current Gain: | ||
* <math>Alpha = \frac{B}{B+1} = \frac{I_{c}}{I_{e}}</math> | * <math>Alpha = \frac{B}{B+1} = \frac{I_{c}}{I_{e}}</math> | ||
V-I Characteristics of Transistors: | |||
* AAAA | |||
NPN Transistor Example: | |||
* Cut Off: Both junction are reverse biased. | |||
* Saturation: Both junction are forward biased. | |||
* Active: One junction is forward biased, another one is reverse biased. | |||
=== Header 2 === | === Header 2 === |
Revision as of 19:42, 2 March 2022
Welcome! Notes for Spring 2022 Electronic Circuits course. Will make this more pretty as things evolve.
My goal is to make Electronic Circuits so easily digestible, you could teach a middle schooler. We'll see if this works.
Prologue
Hey how are you. I will insert something here later. :)
Section 2.1
We'll begin by covering a Bi-polar Junction Transistor, also known as BJT.
What is it exactly? Well, it's a transistor.
- It is a 3 terminal devices.
- It is a unsymmetrical device.
- It amplifies the signal.
There are two types of BJTs:
- NPN, in which...
- PNP, in which...
Now we'll cover (B) Common Emitter Current gain:
- 50 < B < 200
...and (Alpha) Common Base Current Gain:
V-I Characteristics of Transistors:
- AAAA
NPN Transistor Example:
- Cut Off: Both junction are reverse biased.
- Saturation: Both junction are forward biased.
- Active: One junction is forward biased, another one is reverse biased.
Header 2
It sometimes allow current, and sometimes it doesn't.
Assignment 1.1
We'll take this and plug it into to find x2: