MATH511 Linear Algebra Chapter 1

Welcome! Notes for Spring 2022 Linear Algebra course. Will make this more pretty as things evolve.

Wichita State University has standardized their course work for Linear Algebra. Almost all professors will likely adapt to what is being shown below, basically.

My goal is to make Linear Algebra so easily digestible, you could teach a middle schooler. We'll see if this works.

Prologue

Hey how are you. I will insert something here later. :)

Section 1.1

Insert lecture notes here!

Assignment 1.1

We'll be doing 1(b), 5(c), 6(e), 8*, 10 this round from the source textbook.

For 1(b), consider the following:

We'll need to use back substitution to solve this system of linear equation.

{\displaystyle {\begin{aligned}x_{1}+x_{2}+x_{3}=8\\2x_{2}+x_{3}=5\\3x_{3}=9\end{aligned}}}

We'll first need to use substitution to simply and find the values x1, x2, x3. A good rule of thumb is to find the easiest value to simplify that can then be used to find the other values. In this example, x3 can be used to help find x1, x2:

{\displaystyle {\begin{aligned}3x_{3}=9\\x_{3}={\frac {9}{3}}\end{aligned}}}

We'll take this ${\displaystyle x_{3}={\frac {9}{3}}}$ and plug it into ${\displaystyle 2x_{2}+x_{3}=5}$ to find x2:

{\displaystyle {\begin{aligned}2x_{2}+x_{3}=5\\x_{3}={\frac {9}{3}}\\{\text{Plug in }}x_{3}={\frac {9}{3}}{\text{ into }}2x_{2}+x_{3}=5{\text{:}}\\2x_{2}+{\frac {9}{3}}=5\\2x_{2}=2\\x_{2}=1\end{aligned}}}